-0.15x^2-1.6x+79=0

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Solution for -0.15x^2-1.6x+79=0 equation:



-0.15x^2-1.6x+79=0
a = -0.15; b = -1.6; c = +79;
Δ = b2-4ac
Δ = -1.62-4·(-0.15)·79
Δ = 49.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{49.96}}{2*-0.15}=\frac{1.6-\sqrt{49.96}}{-0.3} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{49.96}}{2*-0.15}=\frac{1.6+\sqrt{49.96}}{-0.3} $

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